SOLUTION: find the three consecutive positive odd integers such that the product of the first and the third is 59 more than twice the second.

Algebra ->  Systems-of-equations -> SOLUTION: find the three consecutive positive odd integers such that the product of the first and the third is 59 more than twice the second.      Log On


   

Question 1007429: find the three consecutive positive odd integers such that the product of the first and the third is 59 more than twice the second.
Answer by josgarithmetic(39618) About Me  (Show Source):
You can put this solution on YOUR website!
The numbers are system%282n%2B1%2C2n%2B3%2C2n%2B5%29

Description translates to %282n%2B1%29%282n%2B5%29=59%2B2%282n%2B3%29
algebra steps...
highlight_green%28n%5E2%2B2n-15=0%29

%28n-3%29%28n%2B5%29=0
The specified fact to match was POSITIVE integers, so take this solution as highlight%28n=3%29.

Evaluating the list numbers' expressions, the consecutive positive odd integers
are 7, 9, 11.