SOLUTION: Please help me solve this problem:
A fish is being reeled in at a rate of 30 cm/s from a bridge that is 4m above the water. At what rate is the angle (in rads/s) between the li
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A fish is being reeled in at a rate of 30 cm/s from a bridge that is 4m above the water. At what rate is the angle (in rads/s) between the li
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Question 1007275: Please help me solve this problem:
A fish is being reeled in at a rate of 30 cm/s from a bridge that is 4m above the water. At what rate is the angle (in rads/s) between the line and the water changing when there is 8m of line out ?
fishing line = hypotenuse
4m = height
theta = angle opposite 4m and adjacent water and hypotenuse
Your help is always appreciated! Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! A fish is being reeled in at a rate of 30cm/s from a bridge that is 4m above the water. At what rate is the angle (in rads/s) between the line and the water changing when there is 8m of line out ?
fishing line = hypotenuse
4m= height
theta= angle opposite 4m and adjacent water and hypotenuse
Hypotenuse = c
-------
Angle a = arcsin(4/c)
Differentiate implicitly
da/dt =
dc/dt = -0.3 m/sec
da/dt = (1/sqrt(1 – 16/64))*(-4/64)*(-0.3)
da/dt = (1/sqrt(3/4))*(1.2/64)
= sqrt(3)/80 rad/sec
