Question 1007272: Joseph has 8 coins for a total of $1.40. Some of the coins are nickels and some are quarters. how many of each coin does Joseph have? Answer by tiffany222(56) (Show Source):
You can put this solution on YOUR website! Let nickels be x
Let quarters be y
Nickels are worth $.05
Quarters are worth $.25
x + y = 8
.05x + .25y = 1.40
Multiply second equation by 4 to eliminate y:
x + y = 8
.20x + y = 5.60
Subtract the two equations:
.80x = 2.40
x = 3
Substitute x value to get y value:
x + y = 8
3 + y = 8
y = 5
Final Answer:
3 nickels and 5 quarters
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