SOLUTION: I came up with 30mi....but I can't really explain how I got it. Tom Quig traveled 210 miles east of St. Louis. For most of the trip he averaged 60 mph, but for one period of time h
Algebra ->
Customizable Word Problem Solvers
-> Misc
-> SOLUTION: I came up with 30mi....but I can't really explain how I got it. Tom Quig traveled 210 miles east of St. Louis. For most of the trip he averaged 60 mph, but for one period of time h
Log On
Question 1007225: I came up with 30mi....but I can't really explain how I got it. Tom Quig traveled 210 miles east of St. Louis. For most of the trip he averaged 60 mph, but for one period of time he was slowed to 10 mph due to a major accident. If the total time of travel was 6 hours, how many miles did he drive at the reduced speed? Found 2 solutions by ikleyn, MathTherapy:Answer by ikleyn(52785) (Show Source):
Mathematical model is this system of 2 equations for 2 unknowns
x + y = 210,
+ = 6.
where x is the distance the driver covered at the speed of 60 mph, y is the distance covered at the reduced speed of 10 mph.
The system is consisted and x = 180 mi, y = 30 mi is one possible solution.
Hence, this solution is unique.
The problem is solved.
You can put this solution on YOUR website!
I came up with 30mi....but I can't really explain how I got it. Tom Quig traveled 210 miles east of St. Louis. For most of the trip he averaged 60 mph, but for one period of time he was slowed to 10 mph due to a major accident. If the total time of travel was 6 hours, how many miles did he drive at the reduced speed?
Let distance at reduced speed (10 mph) be D
Then distance traveled at 60 mph = 210 – D
Time traveled at 10 mph:
Time traveled at 60 mph:
We then get:
6D + 210 – D = 360 --------- Multiplying by LCD, 60
6D – D = 360 – 210
5D = 150
D, or distance covered at reduced speed (10 mph) = , or miles
