SOLUTION: Jim and Cindy take eight tests over the semester. Jim's test scores were 83, 95, 76, 90, 72, 84, 65, and 75. Cindy's test scores were: 8

Algebra ->  Average -> SOLUTION: Jim and Cindy take eight tests over the semester. Jim's test scores were 83, 95, 76, 90, 72, 84, 65, and 75. Cindy's test scores were: 8      Log On


   



Question 1007212: Jim and Cindy take eight tests over the semester. Jim's test scores were 83, 95, 76, 90, 72, 84, 65, and 75. Cindy's test scores were: 80, 70, 75, 80, 93, 80, 86, and 89.
Who had the highest average and what is the higher average?

Found 2 solutions by addingup, fractalier:
Answer by addingup(3677) About Me  (Show Source):
You can put this solution on YOUR website!
For each, Jim and Cindy, add up the scores and divide by the number of scores, that will give you the average (it's all calculator work, you don't need my help to work your calculator)

Answer by fractalier(6550) About Me  (Show Source):
You can put this solution on YOUR website!
To find an average, you divide the total scores by the number of tests...
Jim ==> (83+95+76+90+72+84+65+75) / 8 = 80
Cindy ==> (80+70+75+80+93+80+86+89) / 8 = 81.625
Cindy's average is higher at 81.625.