SOLUTION: Find the measures of the angles of an isosceles triangle if the measure of the vertex angle is 40 degrees less than the sum of the measures of the base angles.
I don't know how
Question 100718This question is from textbook Algebra and Trigonometry
: Find the measures of the angles of an isosceles triangle if the measure of the vertex angle is 40 degrees less than the sum of the measures of the base angles.
I don't know how to set this problem up with two different linear equations, I think I got the first one and it's (x+x)-40=180...but I'm not very sure. I need help setting this problem up. This question is from textbook Algebra and Trigonometry
You can put this solution on YOUR website! the base angles are equal.
let x=one of the base angles.
2x+40=180
2x=180-40=140
x=70 divide both sides by 2
so the angles are 70, 70, 40
Ed
You can put this solution on YOUR website! Find the measures of the angles of an isosceles triangle if the measure of the vertex angle is 40 degrees less than the sum of the measures of the base angles.
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Let the equal base angles each have measure "x"
1st: vertex = 2x-40
2nd: vertex + 2x = 180
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2nd: vertex = 180-2x
Substitute in 1st to get:
180-2x = 2x - 40
220 = 4x
x = 55
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So the vertex is 2*55-40 = 70
Each base angle = 55
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Cheers,
Stan H.
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