SOLUTION: A regular hexagon is cut from a square of side 6 inches, a.) what is the apothem of the hexagon? B.) what is the area of the hexagon?

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Question 1007115: A regular hexagon is cut from a square of side 6 inches, a.) what is the
apothem of the hexagon? B.) what is the area of the hexagon?

Answer by Edwin McCravy(20055) About Me  (Show Source):
You can put this solution on YOUR website!
A regular hexagon is cut from a square of side 6 inches, a.) what is
the apothem of the hexagon? B.) what is the area of the hexagon?
The red line below is the apothem.



In the figure 



AB is given 6 inches.  It is divided into 4 parts,
AD = DC = CE = EB = 6/4 = 3/2 inches.

Triangle DOE is equilateral, so DO = DE = DC+CE = 3/2+3/2 = 3 in.

Using the Pythagorean theorem on right triangle DOC,

     DOē = DCē + OCē
      3ē = (3/2)ē + OCē
       9 = 9/4 + OCē
   9-9/4 = OCē
36/4-9/4 = OCē
    27/4 = OCē
   sqrt%2827%2F4%29 = OC
   sqrt%2827%29%2F2 = OC
   sqrt%289%2A3%29%2F2 = OC
   3sqrt%283%29%2F2 = OC = the length of the apothem in inches.

For the area of the hexagon, first we find the area of the 
equilateral triangle DOE:

A%22%22=%22%22expr%281%2F2%29DE%2AOC%22%22=%22%22expr%281%2F2%29%283%29%283sqrt%283%29%2F2%29%22%22=%22%229sqrt%283%29%2F4inē

And as we see below, the hexagon is made up of 6 congruent equilateral
triangles all congruent to DOE, its area is 6 times the area of triangle
DOE.



So the area of the hexagon is 6%2Aexpr%289sqrt%283%29%2F4%29 or 27sqrt%283%29%2F2inē.

Edwin