SOLUTION: The length of a rectangle is 3 ft less than double the width, and the area of the rectangle is 44 ft squared. Find the dimensions of the rectangle.
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-> SOLUTION: The length of a rectangle is 3 ft less than double the width, and the area of the rectangle is 44 ft squared. Find the dimensions of the rectangle.
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Question 1007052: The length of a rectangle is 3 ft less than double the width, and the area of the rectangle is 44 ft squared. Find the dimensions of the rectangle.
You can put this solution on YOUR website! Call the length and width, L and W.
We then have
L = 2W - 3 and
A = area = LW = 44
Substituting in we have
(2W - 3)W = 44
2W^2 - 3W - 44 = 0
(2W - 11)(W + 4) = 0
and
2W = 11
W = 5.5 feet
L = 2(5.5) - 3 = 8 feet
