SOLUTION: In the 6/48 lottery game a player selects six numbers from 1 to 48. What is the probability of selecting at least five of the six winning numbers? (Round your answer to seven decim

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Question 1006995: In the 6/48 lottery game a player selects six numbers from 1 to 48. What is the probability of selecting at least five of the six winning numbers? (Round your answer to seven decimal places.)
Answer by Boreal(15235) About Me  (Show Source):
You can put this solution on YOUR website!
It is two parts:
probability of selecting 5 numbers, and that can be done 6 different ways
(6/48)(5/47)(4/46)(3/45)(2/44)(42/43)*5=30240/768303360
All 6, which would have the same denominator, but numerator would be 6*5*4*3*2*1=720
Add them: 30960/768303360=
0.0000403