SOLUTION: Solve the equation for solutions over the interval [0,2pi) by first solving for the trigonometric equation. 4sinx+6=6

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Question 1006991: Solve the equation for solutions over the interval [0,2pi) by first solving for the trigonometric equation.
4sinx+6=6
Answer by ikleyn(52852) About Me  (Show Source):
You can put this solution on YOUR website!
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Solve the equation for solutions over the interval [0,2pi) by first solving for the trigonometric equation.
4sinx+6=6
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4sinx + 6 = 6.

Subtract 6 from both sides. You will get

4*sin(x) = 0, or sin(x) = 0.

The solutions of the least equations are x = 0, pi%2F4, pi%2F2, 3%2Api%2F4, . . . , 7%2Api%2F4 in the interval [0, 2pi).