SOLUTION: We need to solve this riddle. A two-digit number is 1 more than eight times the sum of the digits. The ones digit is 3 less than the tens digit. What is the number?

Algebra ->  Coordinate Systems and Linear Equations  -> Linear Equations and Systems Word Problems -> SOLUTION: We need to solve this riddle. A two-digit number is 1 more than eight times the sum of the digits. The ones digit is 3 less than the tens digit. What is the number?      Log On


   

Question 1006713: We need to solve this riddle. A two-digit number is 1 more than eight times the sum of the digits. The ones digit is 3 less than the tens digit. What is the number?
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
A two-digit number is 1 more than eight times the sum of the digits. The ones digit is 3 less than the tens digit. What is the number?
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Let the number be 10t+u
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Equation:
10t+u = 8(t+u)+1
u = t-3
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Substitute for "u" and solve for "t"::
10t + t-3 = 8(t+t-3) + 1
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11t - 3 = 16t - 24+1
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11t - 3 = 16t-23
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5t = 20
t = 4
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Then u = t-3 = 1
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Ans: 10t+u = 41
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cheers,
Stan H.
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