SOLUTION: the perimeter of a rectangle is 18 feet. the width of the rectangle is seven less than the width.find the width x-7 is the width and x is the length first solve for x which is 2(x)

Algebra ->  Expressions-with-variables -> SOLUTION: the perimeter of a rectangle is 18 feet. the width of the rectangle is seven less than the width.find the width x-7 is the width and x is the length first solve for x which is 2(x)      Log On


   

Question 1006656: the perimeter of a rectangle is 18 feet. the width of the rectangle is seven less than the width.find the width x-7 is the width and x is the length first solve for x which is 2(x)+2(x-7)+18 I know that you multiply and come out with x=5 then find the width using x-7+_____ inches
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
the perimeter of a rectangle is 18 feet.
the width of the rectangle is seven less than the width.
find the width
x-7 is the width and x is the length
first solve for x which is 2(x)+2(x-7) = 18
I know that you multiply and come out with x=5 then find the width using x-7+_____ inches
=============
Use W & L for clarity.
2W + 2L = 18
W = L-7
------
2(L-7) + 2L = 18
4L = 32
L = 8
W = 1