SOLUTION: Hello, I have been trying to solve this problem for a while now, but can't seem to get it. Here is the problem: 5(B + 3) = 4(B - 7) + 2B I appreciate any help. Thank you.

Algebra ->  Distributive-associative-commutative-properties -> SOLUTION: Hello, I have been trying to solve this problem for a while now, but can't seem to get it. Here is the problem: 5(B + 3) = 4(B - 7) + 2B I appreciate any help. Thank you.      Log On


   

Question 1006553: Hello,
I have been trying to solve this problem for a while now, but can't seem to get it. Here is the problem:
5(B + 3) = 4(B - 7) + 2B
I appreciate any help. Thank you.
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
5(B + 3) = 4(B - 7) + 2B
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5B + 15 = 4B - 28 + 2B
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-B = -43
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B = 43
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Cheers,
Stan H.
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