SOLUTION: Solve the unknown value in the following equation log(base 9)9 ^ log(base 3)3

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Question 1006540: Solve the unknown value in the following equation
log(base 9)9 ^ log(base 3)3
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
+log%28+9%2C+%289%5E%28+log%28+3%2C+3+%29%29+%29%29+
Is this it? If so,
First find +log%28+3%2C+3+%29+
If I say:
+x+=+log%28+3%2C+3+%29+, then the inverse of this is:
+3%5Ex+=+3+
+x+=+1+
+log%28+3%2C+3+%29+=+1+
------------
Now I have:
+log%28+9%2C+9+%29+
+x+=+log%28+9+%2C+9+%29+
+9%5Ex+=+9+
+x+=+1+
+log%28+9%2C+9+%29+=+1+
----------------
The original expression = 1