SOLUTION: Let ln (a)=2, ln (b)=3, ln (c)=5. Solve: f (x)=(ln (c^2))(ln (a^4/b^2))^-1

ln a = 2

ln b = 3

ln c = 5



 ------- Applying  



We therefore have: 



 --- Applying  = ln p – ln q

 ---- Applying  = q ln p

 ----------- Substituting 5 for ln c, 2 for ln a, and 3 for ln b



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