SOLUTION: 1) 7 fl. oz. of a 70% sugar solution was mixed with 3 fl. oz. of pure water. Find the concentration of the new mixture. 2) A metal alloy weighing 12 lb. and containing 4% silver

Algebra ->  Customizable Word Problem Solvers  -> Mixtures -> SOLUTION: 1) 7 fl. oz. of a 70% sugar solution was mixed with 3 fl. oz. of pure water. Find the concentration of the new mixture. 2) A metal alloy weighing 12 lb. and containing 4% silver      Log On

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Question 1006265: 1) 7 fl. oz. of a 70% sugar solution was mixed with 3 fl. oz. of pure water. Find the concentration of the new mixture.
2) A metal alloy weighing 12 lb. and containing 4% silver is melted and mixed with 4 lb, of a different alloy which contains 28% silver. What % of the resulting alloy is silver?
Found 2 solutions by josmiceli, josgarithmetic:
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
(1)
+.7%2A7+=+4.9+ fl oz of sugar in the 70% solution
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The concentration is:
+4.9%2F%28+7+%2B+3+%29+=4.9%2F10+
+4.9%2F10+=+.49+
+.49%2A100+=+49+
The new concentration is 49%
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(2)
+.04%2A12+=+.48+ pounds of silver in 4% alloy
+.28%2A4+=+1.12+ pounds of silver in 28% alloy
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the % silver is:
+%28+.48+%2B+1.12+%29+%2F+%28+12+%2B+4+%29+
+1.6+%2F+16+=+.1+
+.1%2A100+=+10+
10%

Answer by josgarithmetic(39618) About Me  (Show Source):
You can put this solution on YOUR website!
1)
%287%2A70%2B3%2A0%29%2F%287%2B3%29

2)
%2812%2A4%2B4%2A28%29%2F%2812%2B4%29


They are really the same general problem.