SOLUTION: Theodore has a pocket full of nickels and dimes worth $4.20. If there were 15 more dimes than nickels, how many coins were there in Theodore's pocket?

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Question 1006162: Theodore has a pocket full of nickels and dimes worth $4.20. If there were 15 more dimes than nickels, how many coins were there in Theodore's pocket?
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let +n+ = number of nickels
Let +d+ = number of dimes
-------------------------
(1) +d+=+n+%2B+15+
(2) +5n+%2B+10d+=+420+ ( in cents )
---------------------
(1) +-n+%2B+d+=+15+
Multiply both sides of (1) by +5+ and
add the equations
--------------------
(1) +-5n+%2B+5d+=+75+
(2) +5n+%2B+10d+=+420+
-----------------------
+15d+=+495+
+d+=+33+
and
(1) +d+=+n+%2B+15+
(1) +33+=+n+%2B+15+
(1) +n+=+18+
---------------
+33+%2B+18+=+51+
there were 51 coins in his pocket
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check:
(2) +5n+%2B+10d+=+420+
(2) +5%2A18+%2B+10%2A33+=+420+
(2) +90+%2B+330+=+420+
(2) +420+=+420+
OK