Question 1006050: in a triangle ABC, XY is parallel to BC ;AX=9cm , XB=4.5cm and BC =18cm find : (i) AY/YC
(กก)YC/AC
(กกก)XY Answer by dkppathak(439) (Show Source):
You can put this solution on YOUR website! in a triangle ABC, XY is parallel to BC ;AX=9cm , XB=4.5cm and BC =18cm find : (i) AY/YC
(กก)YC/AC
(กกก)XY
solution
By Basic proportion theorem (BPT)
AX/XB=AY/YC
9/4.5=AY/YC
2/1=Ay/YC
(ii)yc/AC=XB/AB corollary BPT
YC/AC=4.5/13.5
YC/AC=1/3
(iii)Ax/AB=XY/BC corollary BPT
9/13.5=xy/BC
2/3=XY/18
3XY=36
XY=12
