SOLUTION: Suppose that a cyclist began a 570 mi ride across a state at the western edge of the state, at the same time that a car traveling toward it leaves the eastern end of the state. If

Algebra ->  Finance -> SOLUTION: Suppose that a cyclist began a 570 mi ride across a state at the western edge of the state, at the same time that a car traveling toward it leaves the eastern end of the state. If       Log On


   

Question 1005986: Suppose that a cyclist began a 570 mi ride across a state at the western edge of the state, at the same time that a car traveling toward it leaves the eastern end of the state. If the bicycle and car met after 9.5 hr and the car traveled 38.6 mph faster than the bicycle, find the average rate of each.
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let +s+ = the speed of the bicycle
+s+%2B+38.6+ = the speed of the car
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Think of this as one of them standing still
( either one ) and the other traveling at
the sum of their speeds
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+570+=+%28+s+%2B+s+%2B+38.6+%29%2A9.5+
+570+=+19s+%2B+366.7+
+19s+=+203.3+
+s+=+10.7+
and
+s+%2B+38.6+=+10.7+%2B+38.6+
+s+%2B+38.6+=+49.3+
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their speeds are:
10.7 mi/hr and 49.3 mi/hr
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check:
+570+=+%28+2s+%2B+38.6+%29%2A9.5+
+570+=+%28+2%2A10.7+%2B+38.6+%29%2A9.5+
+570+=+%28+21.4+%2B+38.6+%29%2A9.5+
+570+=+60%2A9.5+
+570+=+570+
OK