SOLUTION: a train departs at 8:00 A.M. Alternatively, he could ride to the meeting with another sales rep. Bob has an important presentation to deliver at the meeting and needs to arrive as

Algebra ->  Customizable Word Problem Solvers  -> Travel -> SOLUTION: a train departs at 8:00 A.M. Alternatively, he could ride to the meeting with another sales rep. Bob has an important presentation to deliver at the meeting and needs to arrive as       Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


    

Question 1005960: a train departs at 8:00 A.M. Alternatively, he could ride to the meeting with another sales rep. Bob has an important presentation to deliver at the meeting and needs to arrive as early as possible. He knows that the train travels at 80 miles per hour, but has a 30-minute layover halfway through the 156-mile trip. He also knows that his friend cannot depart before 8:00 A.M. and will adamantly refuse to drive any faster than 55 miles per hour. If both methods of transportation leave at the same time (8:00 A.M.), will the train or the car allow him to reach the regional sales meeting on time?
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
The train travels +156+ mi at +80+ mi/hr
+t+=+156%2F80+
+t+=1.95+ hrs
The 30 min layover makes the time for the whole trip
is +.5+%2B+1.95+=+2.45+ hrs
-----------------------
making the trip at +55+ mi/hr:
+t+=+156%2F55+
+t+=+2.836+
------------
Taking the train is the quickest way
+.45%2A60+=+27+
he arrives at 8:00 + 2 hrs
and 27 min, which is 10:27
--------------------------
Going by car:
he arrives at 8:00 + 2 hrs 50.2 min,
which is 10:50 approx.