SOLUTION: Two cars leave a city and head in the same direction.
After 3 hours, the faster car is 18 miles ahead of the
slower car. The slower car has traveled 150 miles. Find
the speed
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-> SOLUTION: Two cars leave a city and head in the same direction.
After 3 hours, the faster car is 18 miles ahead of the
slower car. The slower car has traveled 150 miles. Find
the speed
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Question 1005925: Two cars leave a city and head in the same direction.
After 3 hours, the faster car is 18 miles ahead of the
slower car. The slower car has traveled 150 miles. Find
the speeds of the two cars. Found 2 solutions by fractalier, Edwin McCravy:Answer by fractalier(6550) (Show Source):
You can put this solution on YOUR website! If in three hours the faster car is 18 miles ahead, then it reasons that it goes 6 miles per hour faster (6*3 = 18 miles).
The slower car travels 150 miles in 3 hours, so its speed is
r = d/t = 150 miles / 3 hours = 50 miles per hour
The faster car is then traveling at 56 miles per hour.
You can put this solution on YOUR website! Two cars leave a city and head in the same direction.
After 3 hours, the faster car is 18 miles ahead of the
slower car. The slower car has traveled 150 miles. Find
the speeds of the two cars.
The slower car has traveled 150 miles in 3 hours.
So the slower car's speed is 150 miles in 3 hours or
150 mi per 3 hr, or (150/3) mi/hr or 50 mi/hr.
The faster car has traveled 150+18 or 168 in 3 hours.
So the faster car's speed is 168 miles in 3 hours or
168 mi per 3 hr, or (168/3) mi/hr or 56 mi/hr.
Edwin
