SOLUTION: What is the probability that when drawing two cards, WITHOUT REPLACING, both will be aces?
What is the probability that when drawing two cards, again without replacing, one will
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-> SOLUTION: What is the probability that when drawing two cards, WITHOUT REPLACING, both will be aces?
What is the probability that when drawing two cards, again without replacing, one will
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Question 1005873: What is the probability that when drawing two cards, WITHOUT REPLACING, both will be aces?
What is the probability that when drawing two cards, again without replacing, one will be a heart and the other a club? Answer by rothauserc(4718) (Show Source):
You can put this solution on YOUR website! Probability(drawing two aces) = 4/52 * 3/51 = 1/13 * 1/17 = 0.004524887
Probability(drawing one heart, one club) = (13/52) * (13/51) = 0.06372549
