SOLUTION: log7^0=x rewritten its 7^x=0 dont understand how thats possible or what x should be im working on this for a class

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Question 1005723: log7^0=x rewritten its 7^x=0 dont understand how thats possible or what x should be im working on this for a class
Found 2 solutions by fractalier, MathLover1:
Answer by fractalier(6550) About Me  (Show Source):
You can put this solution on YOUR website!
The log of zero to any base does not exist for the very reason you show.
There is no exponent such that
7^x = 0 or even for any n, n^x = 0.

Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

log%287%2C0%29=x (I guess you have base 7)rewritten its (7%5Ex=0+
recall: log%28b%2C%28y%29%29+=+x is equivalent to (means the exact same thing as) y+=+b%5Ex
in your case base is b=7, y=0, and x=x