SOLUTION: Evaluate each function for the value specified. f(x) = x2 -7x + 10; find (a) f (0), (b)f(5),and(c)f(-2). the X2 above is an X and a little 2 a little hight than the X (to the

Algebra ->  Trigonometry-basics -> SOLUTION: Evaluate each function for the value specified. f(x) = x2 -7x + 10; find (a) f (0), (b)f(5),and(c)f(-2). the X2 above is an X and a little 2 a little hight than the X (to the      Log On


   



Question 100570: Evaluate each function for the value specified.
f(x) = x2 -7x + 10; find (a) f (0), (b)f(5),and(c)f(-2).
the X2 above is an X and a little 2 a little hight than the X (to the root of 2) i think it means?? Help me please?

Answer by bucky(2189) About Me  (Show Source):
You can put this solution on YOUR website!
Before we start you need to know the meaning of x%5E2.
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The 2 is called an exponent and it tells you how many times to multiply x times itself.
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So x%5E2+=+x%2Ax and x%5E3+=+x%2Ax%2Ax and x%5E4+=+x%2Ax%2Ax%2Ax and so on.
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Now to the problem.
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You are given:
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f%28x%29+=+x%5E2+-+7x+%2B+10
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and you are first asked to find f(0). All that means is that you start with the function you
are given and wherever you see an x you substitute zero. Then you evaluate the function:
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so start with:
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f%28x%29+=+x%5E2+-+7x+%2B+10
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then substitute zero for into all the x terms to get:
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f%280%29+=+0%5E2+-+7%2A0+%2B+10
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but note that 0%5E2+=+0%2A0+=+0 and -7%2A0+=+0. When you substitute these values you
are left with:
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f%280%29+=+0+-+0+%2B+10+=+10
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so the answer is: f%280%29+=+10
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Next, you are to find f(5). Start with:
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f%28x%29+=+x%5E2+-+7x+%2B+10
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and wherever you see an x, substitute 5. When you do you get:
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f%285%29+=+5%5E2+-+7%2A5+%2B+10
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but 5%5E2+=+5%2A5+=+25 and -7%2A5=+-35. Substitute these values into the equation and
you get:
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f%285%29+=+25+-+35+%2B+10
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combine these three terms and you get 0. So the answer becomes:
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f%285%29+=+0
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Finally, you are to find f(-2). Start with:
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f%28x%29+=+x%5E2+-+7x+%2B+10
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and substitute -2 for x to get:
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f%28-2%29+=+%28-2%29%5E2+-7%2A%28-2%29+%2B+10
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Note that %28-2%29%5E2+=+%28-2%29%2A%28-2%29+=+4 and -7%2A%28-2%29+=+%2B14. Substitute these values
and you have:
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f%28-2%29+=+4+%2B+14+%2B+10+=+28
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so the answer is:
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f%28-2%29+=+28
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Hope this helps you to understand the equation as well as what the exponents mean.
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