Question 1005669: Josie is sitting on a Ferris wheel. She is exactly 35 feet from the center and is at the 3 o'clock position when the Ferris wheel begins moving.
Define a function f that determines Josie's vertical distance above the horizontal diameter (in feet) as a function of the arc length (in feet), s, swept out by the Ferris wheel as it moves counter-clockwise from the 3 o'clock position.
PLEASE HELP! I am not understanding this. Thanks so much! :)
Answer by Alan3354(69443)   (Show Source):
You can put this solution on YOUR website! Josie is sitting on a Ferris wheel. She is exactly 35 feet from the center and is at the 3 o'clock position when the Ferris wheel begins moving.
Define a function f that determines Josie's vertical distance above the horizontal diameter (in feet) as a function of the arc length (in feet), s, swept out by the Ferris wheel as it moves counter-clockwise from the 3 o'clock position.
=================
vertical distance above the horizontal diameter --> above the center of the wheel.
-----
The start is 0 feet about the center.
Angle with the horizontal
A = arc/r = arc/35 (in radians)
Vertical distance from the center = 35*sin(A)
Vertical distance from the center = 35*sin(arc/35)
--------
email via the TY note if it's not clear.
|
|
|
