SOLUTION: Good day! Can you help me with this problem? Find the volume, lateral surface area, and total surface area of a rectangular pyramid whose height is 10 feet, its length is 6 fee

Algebra ->  Bodies-in-space -> SOLUTION: Good day! Can you help me with this problem? Find the volume, lateral surface area, and total surface area of a rectangular pyramid whose height is 10 feet, its length is 6 fee      Log On


   

Question 1005662: Good day! Can you help me with this problem?
Find the volume, lateral surface area, and total surface area of a rectangular pyramid whose height is 10 feet, its length is 6 feet and its width is 4 feet.
Thank you!
Answer by rothauserc(4718) About Me  (Show Source):
You can put this solution on YOUR website!
A rectangular pyramid has a rectangular base and four triangles (2 pairs)
Volume = (1/3) * area of base * height
Volume = (1/3) * (6*4) + 10 = 80 cubic feet
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h1^2 = 10^2 + 3^2 = 109
h1 = sqrt(109)
area of triangle pair1 = 2 * (1/2) * 4 * sqrt(109) = 41.761226036
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h2^2 = 10^2 + 2^2 = 104
h2 = sqrt(104)
area of triangle pair2 = 2 * (1/2) * 6 * sqrt(104) = 61.188234163
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lateral surface area = 41.761226036 + 61.188234163 = 102.949460199 square feet
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total surface area = 102.949460199 + (6*4) = 126.949460199 square feet
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