SOLUTION: Find the dimensions of a rectangle whose width is 1 inches less than half its length an whose area is 40 square inches.

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Question 1005642: Find the dimensions of a rectangle whose width is 1 inches less than half its length an whose area is 40 square inches.
Answer by CubeyThePenguin(3113) About Me  (Show Source):
You can put this solution on YOUR website!
length = L
width = L/2 - 1

L(L/2 - 1) = 40
L^2/2 - L = 40
L^2 - 2L - 80 = 0
(L - 10)(L + 8) = 0

dimensions: 10 inches by 4 inches