SOLUTION: Bacteria were introduced to a petri dish. Two hours after the introduction, there were 120411 bacteria. After seven hours since the introduction, there were 1083699 bacteria. 1.

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Question 1005594: Bacteria were introduced to a petri dish. Two hours after the introduction, there were 120411 bacteria. After seven hours since the introduction, there were 1083699 bacteria.
1.) Find the growth rate of the bacteria. (round to 3 decimal places)
2.) How many bacteria were initially introduced to the Petri dish? (Round to the nearest bacteria).
3.) How many bacteria will there be after 12 hours? (Round to the nearest bacteria).
4.) How long does it take for the bacteria colony to reach 361233 bacteria? (round to 2 decimal places)
Use Pe^rt equation!
PLEASE HELP ME ! I really have to understand this !

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let +A+ = amount of bacteria after +t+ hrs
+A+=+P%2Ae%5E%28r%2At%29+
You are given 2 points on this growth curve:
( 2, 120411 ) and ( 7, 1083699 )
----------------------------
That will give you 2 equations with 2 unknowns,
so it is solvable
---------------------
(a) +120411+=+P%2Ae%5E%28r%2A2%29+
(b) +1083699+=+P%2Ae%5E%28r%2A7%29+
-----------------------
(1)
You can solve both equations for +P+
(a) +P+=+120411+%2F+e%5E%28r%2A2%29+
(b) +P+=+1083699+%2F+e%5E%28r%2A7%29+
--------------------------
Substitute (a) into (b)
+120411+%2F+e%5E%28r%2A2%29+=+1083699+%2F++e%5E%28r%2A7%29+
Multiply both sides by +e%5E%28r%2A7%29+
++1083699+=+120411+%2A%28+e%5E%28r%2A7%29+%2F+e%5E%28r%2A2%29%29+
Divide both sides by +120411+
+e%5E%28r%2A7%29+%2F+e%5E%28r%2A2%29+=+1083699+%2F+120411+
+e%5E%28r%2A5%29+=+9+
--------------
Take the natural log of both sides
+ln%28+e%5E%28r%2A5%29%29+=+ln%289%29+
+r%2A5+=+2.1972+
+r+=+.439+
--------------------
(2)
Plug this result back into either (a) or (b)
(a) +120411+=+P%2Ae%5E%28r%2A2%29+
(a) +120411+=+P%2Ae%5E%28.439%2A2%29+
(a) +120411+=+P%2Ae%5E.879+
(a) +120411+=+P%2A2.408+
(a) +P+=+50005+
-----------------
(3)
+t+=+12+
+A+=+P%2Ae%5E%28r%2At%29+
+A+=+50005%2Ae%5E%28.439%2A12+%29+
+A+=+50005%2Ae%5E5.268+
+A+=+50005%2A194.03+
+A+=+9702346+
-------------------
(4)
+A+=+P%2Ae%5E%28r%2At%29+
+361233+=+50005%2Ae%5E%28.439t%29+
+e%5E%28.439t%29+=+361233%2F50005+
+e%5E%28.439t%29+=+7.22394++
+ln%28+e%5E%28.439t%29%29+=+ln%287.22394+%29+
+.439t+=+1.9774+
+t+=+4.50+
-------------------
I could easily have made some mistakes, but
I'm pretty sure my methods are OK
You could get other opinions, too.