SOLUTION: The length of a rectangle is
11 yd
less than three times the width, and the area of the rectangle is
70 yd2
. Find the dimensions of the rectangle.
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-> SOLUTION: The length of a rectangle is
11 yd
less than three times the width, and the area of the rectangle is
70 yd2
. Find the dimensions of the rectangle.
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Question 1005562: The length of a rectangle is
11 yd
less than three times the width, and the area of the rectangle is
70 yd2
. Find the dimensions of the rectangle. Answer by Cromlix(4381) (Show Source):
You can put this solution on YOUR website! Hi there,
Make width = 'x'
Length = 3x - 11
Area = width * length (* - times)
70 = x * (3x - 11)
70 = x^2 - 11x
x^2 - 11x - 70 = 0
Factorise:
(3x + 10)(x - 7) = 0
3x + 10 = 0
3x = -10
x = -10/3 (ignored as -ve value)
x - 7 = 0
x = 7
Width = 7 yds
Length = 10 yds
Hope this helps :-)
