SOLUTION: A full house consists of three of one kind and two of another kind. You are dealt a hand of five cards from a standard deck of 52 playing cards. Find the probability of being dealt
Algebra ->
Permutations
-> SOLUTION: A full house consists of three of one kind and two of another kind. You are dealt a hand of five cards from a standard deck of 52 playing cards. Find the probability of being dealt
Log On
Question 1005536: A full house consists of three of one kind and two of another kind. You are dealt a hand of five cards from a standard deck of 52 playing cards. Find the probability of being dealt a full house consisting of three kings. Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! A full house consists of three of one kind and two of another kind. You are dealt a hand of five cards from a standard deck of 52 playing cards. Find the probability of being dealt a full house consisting of three kings.
----
Pick 3 kings:: 4C3 = 4 ways
Pick 2 of another card type:: 12*4C2 = 12*6 = 72 ways
-----
P(full house) = (4*72)/52C5 = 288/2598960 = 0.0001108..
Cheers,
Stan H.
--------
(