SOLUTION: Suppose that a cyclist began a 279 mi ride across a state at the western edge of the state, at the same time that a car traveling toward it leaves the eastern end of the state. If

Algebra ->  Finance -> SOLUTION: Suppose that a cyclist began a 279 mi ride across a state at the western edge of the state, at the same time that a car traveling toward it leaves the eastern end of the state. If       Log On


   



Question 1005457: Suppose that a cyclist began a 279 mi ride across a state at the western edge of the state, at the same time that a car traveling toward it leaves the eastern end of the state. If the bicycle and car met after 4.5 hours and the car traveled 35.8 mph faster than the bicycle, find the average rate of each.
Answer by KMST(5328) About Me  (Show Source):
You can put this solution on YOUR website!
x= average speed of the bicycle, in mph.
So,
x%2B35.8= average speed of the car, in mph,
4.5x= distance covered by the bicycle in 4.5 hours, in miles,
4.5%28x%2B35.8%29= distance covered by the car in 4.5 hours, in miles, and
4.5x%2B4.5%28x%2B35.8%29= total distance covered by the bicycle and car in 4.5 hours, in miles.
Since after 4.5 hours the whole 279 miles of road across the state had been covered between bicycle and car,
4.5x%2B4.5%28x%2B35.8%29=279 is our equation.

Solving:
4.5x%2B4.5%28x%2B35.8%29=279
4.5x%2B4.5x%2B4.5%2A35.8=279
9x%2B161.1=279
9x=279-161.1
9x=117.9
x=117.9%2F9
x=13.1
x%2B35.8=13.1%2B35.8
x%2B35.8=48.9