SOLUTION: The ages of Gary, Gerry and Greggy are consecutive odd integers. Gary is the oldest while Greggy is the youngest. Three years from now, Gary's age will be 8 less than twice Greggy'

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Question 1005426: The ages of Gary, Gerry and Greggy are consecutive odd integers. Gary is the oldest while Greggy is the youngest. Three years from now, Gary's age will be 8 less than twice Greggy's age. What are their present ages?
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let their ages be:
+x+ ( Greggy )
+x%2B2+ ( Gerry )
+x+%2B+4+ ( Gary )
-----------------
+%28+x+%2B+4+%29+%2B+3+=+2%2A%28%28+x+%29+%2B+3+%29+-+8+
+x+%2B+7+=+2x+%2B+6+-+8+
+x+=+7+%2B+2+
+x+=+9+
and
+x%2B2+=+11+
+x+%2B+4+=+13+
--------------
Their ages are 9, 11, and 13
------------------------
check:
Gary is 13
In 3 yrs he will be 16
------------------
In 3 yrs Greggy will be 12
Twice Greggy's age is 24
8 less than 24 is 16
OK