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Question 100529: I've worked these problems over and over and can't seem to find the proper answer.
1. Write the equation of the line passing through each of the given pairs of points. Write your result in slope-intercept form, where possible. (-1, 3) and (4, -2)
I got
m = - 2 - (-3)/4 - (- 1 = -5/5 = -1
m = -1, (x1 – y1)= (-1, 3)
y - 3 = -1 (x -(-1))
y = -x + 1 + 3
y = -x + 4
Is this right???
2. 1. Write the equation of the line passing through each of the given pairs of points. Write your result in slope-intercept form, where possible. (-2, -3) and (2, 0)
I got
m = 0 - (-3)/2-(-2) = 3/4
m = 3/4, (x1, x2) = (-2, -3)
y - (-3) = 3/4 (x-(-2)
y = 3/4x + 2 - 3
y = 3/4 x -1
I know the answer is supposed to be y = 3/4 x - 3/2, but I can't get it... What am I doing wrong???
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! 1. Write the equation of the line passing through each of the given pairs of points. Write your result in slope-intercept form, where possible. (-1, 3) and (4, -2)
I got
m = [- 2 - (3)]/[4 - (- 1)] = -5/5 = -1
That is correct.
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You know the form of the line is y=mx+b
You know m=-1, and y=3 when x=-1, so substitute into the form and solve for "b".
3 = -1*-1+b
b=2
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Therefore the equation is
y = -x + 2
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2. 1. Write the equation of the line passing through each of the given pairs of points. Write your result in slope-intercept form, where possible. (-2, -3) and (2, 0)
I got
m = [0 - (-3)]/[2-(-2)] = 3/4
That is correct.
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m = 3/4, (x1, x2) = (-2, -3)
y - (-3) = (3/4) (x-(-2))
y + 3 = (3/4)x + (3/4)2
y + 3 = (3/4)x + (3/2)
y = (3/4)x +(3/2)-3
y = (3/4)x - (3/2)
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Cheers,
Stan H.
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I know the answer is supposed to be y = 3/4 x - 3/2, but I can't get it... What am I doing wrong???
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