SOLUTION: The length of a rectangle is 3 cm more than the width. If the width is increased by 2 cm and the length is decreased by 1 cm, the figure becomes a square with an area of sq. cms. W

Algebra ->  Customizable Word Problem Solvers  -> Geometry -> SOLUTION: The length of a rectangle is 3 cm more than the width. If the width is increased by 2 cm and the length is decreased by 1 cm, the figure becomes a square with an area of sq. cms. W      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


    

Question 1005089: The length of a rectangle is 3 cm more than the width. If the width is increased by 2 cm and the length is decreased by 1 cm, the figure becomes a square with an area of sq. cms. What is the original perimeter of the rectangle?
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
You omitted the value for the resulting area of the square-formed rectangle after its changes.
Just calling this area, A,

L and w for original dimensions,
L=w%2B3
-
%28w%2B2%29%28L-1%29=A
%28w%2B2%29%28w%2B3-1%29=A
%28w%2B2%29%28w%2B2%29=A
w%2B2=sqrt%28A%29
highlight_green%28w=-2%2Bsqrt%28A%29%29 and this means highlight_green%28L=1%2Bsqrt%28A%29%29.

You can calculate the original perimeter.