SOLUTION: The side of a square house is 24 feet long and the house is located on a lot which is 50 feet longer than it is wide the perimeter of the lot is 20 feet more than five times the pe

Algebra ->  Customizable Word Problem Solvers  -> Misc -> SOLUTION: The side of a square house is 24 feet long and the house is located on a lot which is 50 feet longer than it is wide the perimeter of the lot is 20 feet more than five times the pe      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


    

Question 1005041: The side of a square house is 24 feet long and the house is located on a lot which is 50 feet longer than it is wide the perimeter of the lot is 20 feet more than five times the perimeter of the house find the length of the lot
Answer by fractalier(6550) About Me  (Show Source):
You can put this solution on YOUR website!
Call the lot's width, w. Then its length is w + 50.
Perimeter = 2L + 2W = 2(w + 50) + 2w = 5(4(24)) + 20
Then we get
2w + 100 + 2w = 5(96) + 20
4w + 100 = 480 + 20 = 500
4w = 400
w = 100 feet
The length is 50 feet more, or
150 feet.