SOLUTION: if mary had 14 1/2 reams of paper and dan used 4 8/10 reams and sue used 6 3/5. how much is left over?

Algebra ->  Percentage-and-ratio-word-problems -> SOLUTION: if mary had 14 1/2 reams of paper and dan used 4 8/10 reams and sue used 6 3/5. how much is left over?      Log On


   



Question 1005000: if mary had 14 1/2 reams of paper and dan used 4 8/10 reams and sue used 6 3/5. how much is left over?
Found 2 solutions by fractalier, Alan3354:
Answer by fractalier(6550) About Me  (Show Source):
You can put this solution on YOUR website!
We will subtract the second two fractions from the first and get
14 1/2 - 4 8/10 - 6 3/5 =
14 5/10 - 4 8/10 - 6 6/10 =
Let us borrow one and get
13 15/10 - 4 8/10 - 6 6/10 =
9 7/10 - 6 6/10 =
3 1/10 reams left

Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
if mary had 14 1/2 reams of paper and dan used 4 8/10 reams and sue used 6 3/5. how much is left over?
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14.5 - 4.8 - 6.6 = 3.1 left