SOLUTION: Find the slope-intercept form of the equation that passes through the given point and is perpendicular to the given line.
(6,-1) and 3y+x=3
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(6,-1) and 3y+x=3
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Question 1004991: Find the slope-intercept form of the equation that passes through the given point and is perpendicular to the given line.
(6,-1) and 3y+x=3 Found 2 solutions by stanbon, josgarithmetic:Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! Find the slope-intercept form of the equation that passes through the given point and is perpendicular to the given line.
(6,-1) and 3y+x=3
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Find the slope of the given line::
y = (-1/3)x + 1
slope = -1/3)
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Find the slope of the perpendicular line:
slope = 3
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Equation Form::
y = mx + b
Solve for "b" using the point and the slope values::
-1 = 3(6) + b
b = -19
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Equation:
y = 3x - 19
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Cheers,
Stan H
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