SOLUTION: what is the point {{{P}}} such that {{{abs(AP)/abs(AB)=r}}} for A = (4, -2), B = (-2, -5), {{{r = 2/3}}} where {{{abs(AP)}}} denotes the length of the line segment {{{AP}}}

Algebra ->  Formulas -> SOLUTION: what is the point {{{P}}} such that {{{abs(AP)/abs(AB)=r}}} for A = (4, -2), B = (-2, -5), {{{r = 2/3}}} where {{{abs(AP)}}} denotes the length of the line segment {{{AP}}}      Log On


   



Question 1004906: what is the point P such that abs%28AP%29%2Fabs%28AB%29=r for A = (4, -2), B = (-2, -5), r+=+2%2F3 where abs%28AP%29 denotes the length of the line segment AP
Answer by cparks1000000(5) About Me  (Show Source):
You can put this solution on YOUR website!
The solution is not unique. I am assuming that you are only concerned with real coordinates on the plane. Thus we first calculate the length of
Now we know that P = ( x, y ) and thus .
Next we inspect the expression: +abs%28AP%29%2Fabs%28AB%29+=+r+. We plug in r and abs%28AB%29 and multiply by abs%28AB%29 to yield +abs%28AP%29+=+%282%2F3%29%2A%283%2Asqrt%285%29+%29+=+2+%2A+sqrt%285%29+. Now we square both sides and plug in the expression for abs%28AP%29%5E2. Thus we get the equation +%2820+-+8+x+%2B+x%5E2%29+%2B+%284%29+y+%2B+y%5E2+=+20+. Then we subtract 20 to yield +%288+x+%2B+x%5E2%29+%2B+%284%29+y+%2B+y%5E2+=+0+.
Now is a tricky part. We have two unknowns x and y and only one equation. Thus there are infinitely many solutions. Thus we can choose x to be anything, then solve for y. Set +a+=+1, +b=+4, and c=-8x+%2B+x%5E2, then our equation simply looks like the standard quadratic a%2Ay%5E2+%2B+b%2Ay+%2B+c+=+0 Then we use the quadratic equation to yield . Here I remark that only positive things can be inside the square root. Thus we must choose x such that +c+%3C=+4 implies +-+8x+%2B+x%5E2+%3C=+4 implies +-4+-+8x+%2B+x%5E2+%3C=0+. Now we factor the quadratic using the quadratic formula: . We plug this into the inequality and note that x=0 is a solution to yield that +%28+x+-+%284%2Bsqrt%2820%29%29+%29%28x-%284-sqrt%2820%29%29+%29+%3C=+0+ This implies that x has solutions in the set [4-sqrt%2820%29, 4%2Bsqrt%2820%29 ].
One particular solution occurs when x = 0. Thus in this case, c=0 and we can take the positive version of the square root to yield +y+=+-2+%2B+sqrt%284%29+
Check the answer:
+abs%28AP%29%5E2+=+16+%2B+%28-+sqrt%284%29%29%5E2+=+16++%2B+4+=+20+.
Thus