SOLUTION: Sharon plans to mix peppermints worth $1.20 per lb with chocolates worth $2.40 per lb to get a 40 lb mix that is worth $1.65 per lb. How much of each should she use?

Algebra ->  Customizable Word Problem Solvers  -> Travel -> SOLUTION: Sharon plans to mix peppermints worth $1.20 per lb with chocolates worth $2.40 per lb to get a 40 lb mix that is worth $1.65 per lb. How much of each should she use?      Log On

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Question 1004880: Sharon plans to mix peppermints worth $1.20 per lb with chocolates worth
$2.40 per lb to get a 40 lb mix that is worth $1.65 per lb. How much of each
should she use?

Answer by addingup(3677) About Me  (Show Source):
You can put this solution on YOUR website!
p+c= 40lb subtract p from both sides: c= 40-p Used this in the next formula:
1.20p+2.40c= 1.65(40) Now substitute for c:
1.20p+2.40(40-p)= 1.65(40)
1.20p+96-2.40p= 66
-1.2p= -30
p= -30/-1.2= 25lbs of peppermint and
c= 40-25= 15 lbs of chocolate