SOLUTION: Find the point on each median that is two-thirds of the distance from the vertec to the midpoint if the vertices of the triangle are A (4,-4), B (10,4) & C (2,6)

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Question 1004861: Find the point on each median that is two-thirds of the distance from the vertec to the midpoint if the vertices of the triangle are A (4,-4), B (10,4) & C (2,6)
Answer by MathLover1(20849) About Me  (Show Source):
You can put this solution on YOUR website!
The midpoints are
(7,0),(6,5),(3,1)

The midpoint of the triangle is %282%2F3%29s the length of the median.
Find one vertex, and go %282%2F3%29s the way to the midpoint of the opposite side. Directions matter. Start at the point, and take %282%2F3%29s the x value and %282%2F3%29s the y value.
The easiest one is %282%2F3%29s from (2,6) to (7,0)
The x-value is %282%2F3%29s from 2 to 7. The distance is 5, and %282%2F3%29s of that is %2810%2F3%29, or 3.33.
So the x-value is 5.33 or 16%2F3.

The y-value is %282%2F3%29s from 6 to 0, or %282%2F3%296=4. The y-value is 2.
The midpoint is (16%2F3,2).
This will work for the other two points to the opposite side midpoint.


or, you can do it this way:
take two vertices and two midpoints and find the equations of the lines passing through one midpoint and opposite vertices
R(7,0) and C (2,6)
Solved by pluggable solver: Find the equation of line going through points
hahaWe are trying to find equation of form y=ax+b, where a is slope, and b is intercept, which passes through points (x1, y1) = (7, 0) and (x2, y2) = (2, 6).
Slope a is a+=+%28y%5B2%5D-y%5B1%5D%29%2F%28x%5B2%5D-x%5B1%5D%29+=+%286-0%29%2F%282-7%29+=+-1.2.
Intercept is found from equation a%2Ax%5B1%5D%2Bb+=+y%5B1%5D, or -1.2%2A7+%2Bb+=+8.4. From that,
intercept b is b=y%5B1%5D-a%2Ax%5B1%5D, or b=0--1.2%2A7+=+8.4.

y=(-1.2)x + (8.4)

Your graph:




Q(6,5) and A (4,-4)
Solved by pluggable solver: Find the equation of line going through points
hahaWe are trying to find equation of form y=ax+b, where a is slope, and b is intercept, which passes through points (x1, y1) = (6, 5) and (x2, y2) = (4, -4).
Slope a is a+=+%28y%5B2%5D-y%5B1%5D%29%2F%28x%5B2%5D-x%5B1%5D%29+=+%28-4-5%29%2F%284-6%29+=+4.5.
Intercept is found from equation a%2Ax%5B1%5D%2Bb+=+y%5B1%5D, or 4.5%2A6+%2Bb+=+-22. From that,
intercept b is b=y%5B1%5D-a%2Ax%5B1%5D, or b=5-4.5%2A6+=+-22.

y=(4.5)x + (-22)

Your graph:




so, your equations are:
y=-1.2x+%2B+8.4 and
y=4.5x+-22
-----------------find intersection
since left sides equal, make right sides equal and solve for x
4.5x+-22=-1.2x+%2B+8.4
4.5x+%2B1.2x+=22%2B+8.4
5.7x++=30.4
x++=30.4%2F5.7
x++=304%2F57
x+=+16%2F3
find y
y=4.5%2816%2F3%29+-22
y=45%2816%2F30%29+-%2822%2A30%29%2F30
y=720%2F30+-660%2F30
y=60%2F30
y=2


intersection point is at (16%2F3,2) and that is your midpoint