SOLUTION: Three times the least of three consecutive odd integers exceeds twice the greater by 17. Find the three integers.

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Question 1004842: Three times the least of three consecutive odd integers exceeds twice the greater by 17. Find the three integers.
Answer by vleith(2983) About Me  (Show Source):
You can put this solution on YOUR website!
Let the smallest odd number be x. Then the next two odd numbers will be (x+2) and (x+4)
You are told
3%2Ax+=+%282%2A%28x%2B4%29%29+%2B+17
3x+=+2x+%2B+8+%2B+17
3x+=+2x+%2B+25
x+=+25
So the numbers are 25, 27, and 29
Check you answer. Does 3*25 = 2* 29 + 17 ??