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| Question 1004794:  The line segment joining a vertex of a triangle and the midpoint of the opposite side is called median of the triangle, the vertices of the triangle are A (4,-4), B (10,4) & C (2,6). Find the point on each median that is two-thirds of the distance from the vertex to the midpoint of the opposite side
 Answer by Boreal(15235)
      (Show Source): 
You can put this solution on YOUR website!  Midpoints of each side is the average of the x values and y values of each end.
 The midpoints are
 (7,0),(6,5),(3,1)
 The midpoint of the triangle is 2/3s the length of the median.
 Find one vertex, and go 2/3s the way to the midpoint of the opposite side.  Directions matter. Start at the point, and take 2/3s the x value and 2/3s the y-value.
 The easiest one is 2/3s from (2,6) to (7,0)
 The x-valueis  2/3s from 2 to 7.  The distance is 5, and 2/3 of that is 10/3, or 3 1/3.  So the x-value is 5 1/3 or 16/3. The y-value is 2/3 s from 6 to 0, or 2/3 of 6=4.  The y-value is 2.
 The midpoint is (16/3,2).
 This will work for the other two points to the opposite side midpoint.
 
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