SOLUTION: A basketball player hits three-point shots 46% of the time. If she takes 4 shots during a game, what is the probability that she misses the first shot and hits the last three shots
Algebra ->
Probability-and-statistics
-> SOLUTION: A basketball player hits three-point shots 46% of the time. If she takes 4 shots during a game, what is the probability that she misses the first shot and hits the last three shots
Log On
Question 1004750: A basketball player hits three-point shots 46% of the time. If she takes 4 shots during a game, what is the probability that she misses the first shot and hits the last three shots? Answer by fractalier(6550) (Show Source):
You can put this solution on YOUR website! Multiply the individual shot probabilities...
so we have (for 46% to make it and 54% to miss)...
P = .54*.46*.46*.46 = 0.0526 = 5.26%
