SOLUTION: Find two consecutive even integers such that twice the smaller is 10 more than the larger
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Question 1004732
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Find two consecutive even integers such that twice the smaller is 10 more than the larger
Answer by
fractalier(6550)
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Call the integers x and x+2.
Then, from the facts of the problem, we have
2x = 10 + (x+2)
and then
2x = x + 12
x = 12
x+2 = 14
