SOLUTION: The sum of the areas of two squares is 89 square centimeters. The length of a side of the larger square is 3 centimeters more than the length of a side of the smaller square. Find

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Question 1004450: The sum of the areas of two squares is 89 square centimeters. The length of a side of the larger square is 3 centimeters more than the length of a side of the smaller square. Find the dimensions of each square.
Answer by mananth(16946) About Me  (Show Source):
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The sum of the areas of two squares is 89 square centimeters. The length of a side of the larger square is 3 centimeters more than the length of a side of the smaller square. Find the dimensions of each square.

the length of a side of the smaller square. let it be x
Area = x^2

The length of a side of the larger square is 3 centimeters more than .(x+3)
area = (x+3)^2
The sum of the areas of two squares is 89 square centimeters.
x^2+(x+3)^2=89
x^2+x^2+6x+9 = 89
2x^2+6x-80=0
/2
x^2+3x-40=0
x^2+8x-5x-40=0
x(x+8)-5(x+8)=0
(x+8)(x-5)=0
x=-8 OR x= 5
Ignore negative
dimensions of the squares are
5 by 5 cm and 8 by 8 cm