SOLUTION: Please help me solve this equation: {{{x^2+sqrt(x)=2}}}. I know x=1 but I want to know the procedure.

Algebra ->  Systems-of-equations -> SOLUTION: Please help me solve this equation: {{{x^2+sqrt(x)=2}}}. I know x=1 but I want to know the procedure.      Log On


   



Question 1004388: Please help me solve this equation: x%5E2%2Bsqrt%28x%29=2.
I know x=1 but I want to know the procedure.

Answer by richard1234(7193) About Me  (Show Source):
You can put this solution on YOUR website!
Without any computation, x = 1 *has* to be the only real solution because the functions x^2 and sqrt(x) are strictly increasing when x >= 0 (note: if x < 0, then the LHS is non-real). Because x = 1 is a solution, it must be the only real solution.

Assuming complex-valued square roots, you can solve by isolating sqrt(x) and squaring:



And so on.