SOLUTION: Find three consecutive integers such that the sum of the largest and 5 times the smallest is -244.

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Question 1004382: Find three consecutive integers such that the sum of the largest and 5 times the smallest is -244.
Found 2 solutions by fractalier, Cromlix:
Answer by fractalier(6550) About Me  (Show Source):
You can put this solution on YOUR website!
Call the first one x. The next two are x+1 and x+2. Then we have
(x+2) + 5x = -244
6x + 2 = -244
6x = -246
x = -41
The numbers are then
-41, -40, and -39.

Answer by Cromlix(4381) About Me  (Show Source):
You can put this solution on YOUR website!
Hi there,
Three consecutive integers.
n + (n + 1) + (n + 2)
the sum of the largest and 5 times the smallest is -244.
(n + 2) + 5(n) = -244
n + 2 + 5n + -244
Collect like terms
n + 5n = -244 - 2
6n = -246
n = -41
Three consecutive integers
-41, -40, -39.
the sum of the largest and 5 times the smallest is -244.
-39 + 5(-41) = -244
-39 + -205 = -244
Hope this helps :-)