SOLUTION: The perimeter of a rectangle is 24 cms. If the length is increased by 4 and the width is decreased by 2, the area is decreased by 2 sq. cms. What are the dimensions of the original

Algebra ->  Rectangles -> SOLUTION: The perimeter of a rectangle is 24 cms. If the length is increased by 4 and the width is decreased by 2, the area is decreased by 2 sq. cms. What are the dimensions of the original      Log On


   

Question 1004245: The perimeter of a rectangle is 24 cms. If the length is increased by 4 and the width is decreased by 2, the area is decreased by 2 sq. cms. What are the dimensions of the original rectangle?
Answer by jkc52(5) About Me  (Show Source):
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let the length and width of the original rectangle be l and b cm.
given that the perimeter of the rectangle is 24 cm
therefore 2*(l+b)=24
or l +b =12........................(1)
the area of this rectangle a1=l*b
as per the second condition (l+4)*(b-2)=a1-2
therefore
-2*l+4*b+l*b-8=a1-2
or l-2*b=-3.......................(2)
therefore solving 1 and 2 l=7 and b =5 cm