Question 1004026: A large corporation would like to estimate the proportion of their employees that have children. The director of human resources takes a random sample of 102 employees and find that 76% of them have children. Calculate a 95% confidence interval for the proportion of all employees at this company that have children (use the traditional formula).
What is the lower bound of the confidence interval?
What is the upper bound of the confidence interval?
Answer by Boreal(15235)   (Show Source):
You can put this solution on YOUR website! This is a one-sample proportion test
standard error is sqrt (p)(1-p)/n=
sqrt (0.76)*(0.24)/102=0.04223
without rounding, the half CI is 1.96*SE=0.0829
The whole CI is (0.68,0.84), keeping two decimal places. One can make it three or four decimal places, but it is already rounded by using 76%, which is not the true number, since 76% of 102=77.52
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