SOLUTION: Let f be a function such that f(-1) = 3 and f(2) = -4. The coordinates of two points on the graph of y = 3f(-x) - 2 are.

Algebra ->  Functions -> SOLUTION: Let f be a function such that f(-1) = 3 and f(2) = -4. The coordinates of two points on the graph of y = 3f(-x) - 2 are.      Log On


   

Question 1003808: Let f be a function such that f(-1) = 3 and f(2) = -4. The
coordinates of two points on the graph of y = 3f(-x) - 2
are.
Answer by Edwin McCravy(20064) About Me  (Show Source):
You can put this solution on YOUR website!
Let f be a function such that f(-1) = 3 and f(2) = -4. The
coordinates of two points on the graph of y = 3f(-x) - 2
are ?
We just have to be very careful with our signs:

Start with

y+=+3f%28-x%5E%22%22%29+-+2

Substitute 1 for x

y+=+3f%28-%281%29%5E%22%22%29+-+2

y+=+3f%28-1%29+-+2

Substitute 3 for f(-1) since that is given

y+=+3%283%29+-+2

y+=+9+-+2

y+=+7

So one point is (x,y) = (1,7)

Again start with

y+=+3f%28-x%5E%22%22%29+-+2

Substitute -2 for x

y+=+3f%28-%28-2%29%5E%22%22%29+-+2

y+=+3f%282%29+-+2

Substitute -4 for f(2) since that is given

y+=+3%28-4%29+-+2

y+=+-12+-+2

y+=+-14

So another point is (x,y) = (-2,-14)

Edwin